Showing posts with label Train. Show all posts
Showing posts with label Train. Show all posts
Monday, 20 May 2019
Thursday, 4 April 2019
Train Formulas
Conversion:
km/hr to m/s conversion:
m/s to km/hr conversion:
Formulas for finding Speed, Time and Distance
1. Time taken by a train of length l metres to pass a pole or standing man or a signal post is equal to the time taken by the train to cover l metres.
2. Time taken by a train of length l metres to pass a stationary object of length b metres is the time taken by the train to cover (l + b) metres.
3. Suppose two trains or two objects bodies are moving in the same direction at u m/s and v m/s, where u > v, then their relative speed is = (u - v) m/s.
4. Suppose two trains or two objects bodies are moving in opposite directions at u m/s and v m/s, then their relative speed is = (u + v) m/s.
5. If two trains of length a metres and b metres are moving in opposite directions at u m/s and v m/s, then:
Time taken by the trains to cross each other=
|
6. If two trains of length a metres and b metres are moving in the same direction at u m/s and v m/s, then:
Time taken by the faster train to cross the Slow Train=
|
(A's speed) : (B's speed) = (b : a)
Example sum
1) A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Speed = [ 60 * (5 / 18 ) ] m/sec
= ( 50 / 3 ) m/sec
Length of the train = ( Speed * Time )
= [( 50/3)*9 ] m= 150m
2) A train 125 m long passes a man, running at 5 km/hr in the same direction in whichthe train is going, in 10 seconds. Find the speed of the train?
Speed of the train relativeto man = ( 125 /10 ) m/sec
= ( 25 / 2 ) m/sec
= [(25/2) * ( 18/5) ] km/hr
= 45 km/hr
Let the speed of the train be x km/hr.
Relative speed = (x - 5 ) km/hr.
(x-5)=45
x = 45+5x
= 50 km/hr
Basic Formulas
If two trains of p meters and q meters are moving in same direction at the speed of x m/s and y m/s ( x > y ) respectively then time taken by the faster train to overtake slower train is given by = [ (p + q)/ (x -y)]
Example sum
3)Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr.The faster trainpasses the slower train in 36 seconds.Find the length of each train?
Let the length of each train be x metres.
Distance covered = 2x metres.
Relative speed = ( 46 - 36 ) km/hr
= [ 10*(5/18) ] m/sec
= ( 25/9) m/sec
= ( 2x/36) = ( 25/9)
= 2x=100
x = 50
Basic Formulas
If two trains of p meters and q meters are moving in opposite direction at the speed of x m/s and y m/s respectively then time taken by trains to cross each other is given by = [ (p + (x + y)]
Example sum
4) Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction?
Speed of the first train = ( 120 / 10 )m/sec
= 12 m/sec
Speed of the second train = ( 120 / 15 )m/sec
= 8 m/sec
Relative speed = ( 12 + 8 )
= 20 m/sec
Required time = [ ( 120 + 120 ) / 20 ] sec
= 12 sec
Tuesday, 2 April 2019
Wednesday, 13 March 2019
Sunday, 3 March 2019
Aptitude Hack#4(27-2-19)
Question:
Three friends started running together on a circular track at 8:00:00 am. Time taken by them to complete one round of the track is 15 min, 20 min, 30 min respectively. If they run continuously without any halts, then at what time will they meet again at the starting point for the fourth time?
A ) 8:30:00 am
B ) 9:00:00 pm
C )12:00:00 pm
D )12:00:00 am