The Interview Question Today#24(19-3-19)

Question:

Given the perimeter of a rectangle, the task is to find the maximum area of a rectangle which can be formed.

Example:

Input: perimeter = 15

Output: Maximum Area = 12

Solution:

Approach:

For the area to be maximum of any rectangle the difference of length and breadth must be minimal. So, in such case, the length must be ceil (perimeter / 4) and breadth will be floor(perimeter /4).

 Hence the maximum area of a rectangle with a given perimeter is equal to ceil(perimeter/4) * floor(perimeter/4).

C program:

#include<stdio.h>

// Function to find max area

float maxArea(float perimeter)

{

int length = (int)ceil(perimeter / 4);

int breadth = (int)floor(perimeter / 4);

// return area

printf("Length=%d \nBreath=%d\n",length,breadth);

return length * breadth;

}

int main()

{

float n;

printf("Enter the Perimeter\n");

scanf("%f",&n);

printf("Maximum Area = %f",maxArea(n));

return 0;

}

Output:

Enter the Perimeter

30

Length=8

Breath=7

Maximum Area = 56.000000