The Interview Question Today#107(10-6-19)

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Write a program print the pattern { 1,1,2,3,4,9,8,27,16,81,32,243.}

Question:

Credits: Swathi.

#include<stdio.h>
void main(){
     int n;
//As we are taking it in pair.
printf("Enter the limit in pairs:"); 
scanf("%d",&n);
     int even=1,odd=1;
   int i;
for(i=0;i<n;i++)
{
printf("%d,%d,",even,odd);
even*=2;
odd*=3;
}
}

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The Interview Question Today#113(16-9-19)

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The Interview Question Today#112(15-6-19)

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The Interview Question Today#110(13-6-19)

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The Interview Question Today#109(12-6-19)

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Tricky Interview#6

Question:

WAC PROGRAM THAT GIVES THE SIZE OF STRING WITHOUT USING ANY FUNCTION(PRE DEFINED OR USER DEFINED), NO LOOPS AND NO RECURSION.

Solution:

#include<stdio.h>
void main()
{
int a[100],n;
printf("Enter the String\n");
scanf("%s",a);
n=printf("%s\n",a);
printf("%d",n-1);
}

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Tricky Interview#5

Question:
How would you write a C program to print 1 to 100 without loop, recursion, or goto?

Solution:

#include<stdio.h>

void hundred() { static int i=1; printf("%d\n",i++); }

void  twenty(){ hundred(),hundred(),hundred(),hundred(),hundred(); }

void four() { twenty(),twenty(),twenty(),twenty(),twenty(); }

int main()
{
    four(),four(),four(),four();

}

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The Interview Question Today#106(9-6-19)

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The Interview Question Today#102(5-6-19)

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C program to print the truth table for XY+Z

C program to print the truth table for XY+Z  

#include<stdio.h>
#include<conio.h>

void main()
{
int x,y,z;
clrscr(); //to clear the screen
printf(“XtYtZtXY+Z”);

for(x=0;x<=1;++x)
for(y=0;y<=1;++y)
for(z=0;z<=1;++z)
{
if(x*y+z==2)
printf(“nn%dt%dt%dt1”,x,y,z);
else
printf(“nn%dt%dt%dt%d”,x,y,z,x*y+z);
}
}

OUTPUT:

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Print “javaabhigyan” with empty main() in C

Write a program that prints “javaabhigyan” with empty main() function.You are not allowed to write anything in main().

1.) One way of doing this is to apply GCC constructor attribute to a function so that it executes before main()

#include <stdio.h> 
  
/* Apply the constructor attribute to myStartupFun()  
   so that it is executed before main() */
void myStartupFun(void) __attribute__((constructor)); 
  
/* implementation of myStartupFun */
void myStartupFun(void) 
{ 
    printf("javaabhigyan"); 
} 
  
int main() 
{ 
} 

Output:
javaabhigyan

2.) In linux, just override the default definition of _start() function so that it would work as a custom startup code. See this article to understand more.

#include <stdio.h> 
#include <stdlib.h> 
  
int main(void) 
{ 
} 
  
// _start() function 
void _start(void) 
{ 
    printf("javaabhigyan"); 
  
    // Call main() function 
    int var = main(); 
    exit(var); 
} 

Now compile this by following command

gcc -nostartfiles -o file file.c

Output:
javaabhigyan

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Compute average of two numbers without overflow

Given two numbers, a and b. Compute the average of the two numbers.

The well know formula (a + b) / 2 may fail at the following case :
If, a = b = (2^31) – 1; i.e. INT_MAX.
Now, (a+b) will cause overflow and hence formula (a + b) / 2 wont work

Improved Formula that does not cause overflow :

Average = (a / 2) + (b / 2) + (((a % 2) + (b % 2)) / 2)


Below is the implementation :

// C code to compute average of two numbers 
#include <stdio.h>
#define INT_MAX 2147483647
// Function to compute average of two numbers 
int compute_average(int a, int b) 
{ 
    return (a / 2) + (b / 2) + ((a % 2 + b % 2) / 2); 
} 
  
  int main() 
{ 
    // Assigning maximum integer value 
    int a = INT_MAX, b = INT_MAX; 
  
    // Average of two equal numbers is the same number 
    printf("Actual average : %d\n",INT_MAX); 
  
    // Function to get the average of 2 numbers 
    printf("Computed average : %d",compute_average(a, b)); 
  
    return 0; 
} 

Output:
Actual average: 2147483647
Computed average: 2147483647

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Implementing ternary operator without any conditional statement

How to implement a ternary operator in C without using conditional statements.

In the following condition : a ? b : c
If a is true, b will be executed.
Otherwise, c will be executed.

We can assume a, b and c as values.


We can code the equation as :
Result = (!!a)*b + (!a)*c
In above equation, is a is true, result will be b.
Otherwise, the result will be c.


// C code to implement ternary operator
#include<stdio.h>

// Function to implement ternary operator without
// conditional statements
int ternaryOperator(int a, int b, int c)
{
    // If a is true, we return (1 * b) + (!1 * c) i.e. b
    // If a is false, we return (!1 * b) + (1 * c) i.e. c
    return ((!!a) * b + (!a) * c);
}

// Driver code
int main()
{
    int a = 0, b = 10, c = 20;

    // Function call to output b or c depending on a
    printf("%d",ternaryOperator(a, b, c));

    return 0;
}

Output:
20

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Conditionally assign a value without using conditional and arithmetic operators

Asked in: Google Interview

Given 4 integers a, b, y, and x, where x can only either 0 and 1 only. The ask is as follows:

If 'x' is 0, 
   Assign value 'a' to variable 'y' 
Else (If 'x' is 1)
   Assign value 'b' to variable 'y'.

Note: – You are not allowed to use any conditional operator (including the ternary operator) or any arithmetic operator ( +, -, *, /).

Examples :

Input :  a = 5 , b = 10, x = 1
Output :  y = 10

Input : a = 5, b = 10 , x = 0
Output :  y = 5


An Idea is to simply store both 'a' and  'b' 
in an array at 0th and 1st index respectively.
Then store value to 'y' by taking 'x' as the index.
Below is implementation

// C program  to assign value to y according 
// to value of x 
  
#include<stdio.h> 
  
// Function to assign value to y according 
// to value of x 
int assignValue(int a, int b, int x) 
{ 
    int y; 
    int arr[2]; 
  
    // Store both values in an array 
    // value 'a' at 0th index 
    arr[0] = a; 
  
    // Value 'b' at 1th index 
    arr[1] = b; 
  
    // Assign value to 'y' taking 'x' as index 
    y = arr[x]; 
  
    return y; 
} 
  
int main() 
{ 
    int a = 5; 
    int b = 10; 
    int x = 0; 
  
printf("Value assigned to 'y' is %d", assignValue(a, b, x); 
    return 0; 
} 

Output :
Value assigned to 'y' is 5

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C Program to convert Number in Characters

Number in characters conversion: In c language, we can easily convert the number in characters by the help of loop and switch case. In this program, we are taking input from the user and iterating this number until it is 0. While iteration, we are dividing it by 10 and the remainder is passed in switch case to get the word for the number.

Let's see the c program to convert the number in characters.

#include<stdio.h>    
#include<stdlib.h>  
int main(){  
long int n,sum=0,r;    
system("cls");  
printf("enter the number=");    
scanf("%ld",&n);    
while(n>0)    
{    
r=n%10;    
sum=sum*10+r;    
n=n/10;    
}    
n=sum;    
while(n>0)    
{    
r=n%10;    
switch(r)    
{    
case 1:    
printf("one ");    
break;    
case 2:    
printf("two ");    
break;    
case 3:    
printf("three ");    
break;    
case 4:    
printf("four ");    
break;    
case 5:    
printf("five ");    
break;    
case 6:    
printf("six ");    
break;    
case 7:    
printf("seven ");    
break;    
case 8:    
printf("eight ");    
break;    
case 9:    
printf("nine ");    
break;    
case 0:    
printf("zero ");    
break;    
default:    
printf("tttt");    
break;    
}    
n=n/10;    
}    
return 0;  
}  

Output:

enter the number=4321
four three two one  

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C Program to generate Fibonacci Triangle

In this program, we are getting input from the user for the limit for the fibonacci triangle, and printing the Fibonacci series for the given number of times (limit).

Let's see the c example to generate Fibonacci triangle.

#include<stdio.h>    
#include<stdlib.h>  
int main(){  
   int a=0,b=1,i,c,n,j;    
system("cls");  
    printf("Enter the limit:");    
    scanf("%d",&n);    
    for(i=1;i<=n;i++)    
    {    
        a=0;    
        b=1;    
        printf("%d\t",b);    
        for(j=1;j<i;j++)    
        {    
            c=a+b;    
            printf("%d\t",c);    
            a=b;    
            b=c;        
        }    
        printf("\n");    
    }    
return 0;  
}  

Output:

Enter the limit:9
1
1 1
1 1 2
1 1 2 3
1 1 2 3 5
1 1 2 3 5 8
1 1 2 3 5 8 13
1 1 2 3 5 8 13 21
1 1 2 3 5 8 13 21 34

Enter the limit:5
1
1 1
1 1 2
1 1 2 3
1 1 2 3 5

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C Program to print Number Triangle

Like the alphabet triangle, 
we can write the c program to print the number triangle. The number triangle can be printed in different ways.

Let's see the c example to print number triangle.

#include<stdio.h>    
#include<stdlib.h>  
int main(){  
  int i,j,k,l,n;    
system("cls");  
printf("enter the range=");    
scanf("%d",&n);    
for(i=1;i<=n;i++)    
{    
for(j=1;j<=n-i;j++)    
{    
printf(" ");    
}    
for(k=1;k<=i;k++)    
{    
printf("%d",k);    
}    
for(l=i-1;l>=1;l--)    
{    
printf("%d",l);    
}    
printf("\n");    
}    
return 0;  
}  

Output:

enter the range= 4
   1
  121
 12321
1234321 

enter the range= 7
      1
     121
    12321
   1234321
  123454321
 12345654321
1234567654321

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C Program to print Alphabet Triangle

There are different triangles that can be printed. Triangles can be generated by alphabets or numbers.
 In this c program, we are going to print alphabet triangles.

Let's see the c example to print alphabet triangle.

#include<stdio.h>    
#include<stdlib.h>  
int main(){  
  int ch=65;    
    int i,j,k,m;    
  system("cls");  
    for(i=1;i<=5;i++)    
    {    
        for(j=5;j>=i;j--)    
            printf(" ");    
        for(k=1;k<=i;k++)    
            printf("%c",ch++);    
            ch--;    
        for(m=1;m<i;m++)    
            printf("%c",--ch);    
        printf("\n");    
        ch=65;    
    }    
return 0;  
}  

Output:

     A
    ABA
   ABCBA
  ABCDCBA
 ABCDEDCBA

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C Program without main() function

We can write c program without using the main() function. 
To do so, we need to use the #define preprocessor directive.

Let's see a simple program to print "hello" without main() function.

#include<stdio.h>    
 #define start main    
void start() {    
   printf("Hello");    
}   

Output:

Hello

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